What is the value for ΔS°reaction for the following reaction, given the standard entropy values
C6H12O6(s) + 6O2(g) —-> 6CO2(g) + 6H2O(l)

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Standard entropy of the compounds of interest are as follows,  = 212.1 J/K.mol = 205.0 J/K.mol = 213.6 J/K.mol = 69.9 J/K.mol Now for the reaction:  C6H12O6(s) + 6O2(g) —->6CO2(g) + 6H2O(l) ΔS°reaction = ∑ - ∑ ∴ ΔS°reaction =( 6 + 6  ) - ( + 6 = 205.0 J/K.mol) ∴ ΔS°reaction = [6 (213.6) + 6 (69.9 )] - [(212.1) + 6(205.0)] ∴ ΔS°reaction = 258.9


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The answer is C. 262 J/ K mol. Molar mass: C6H12O6212.1 J/K.mol O2= 205.0 J/K.mol CO2 = 213.6 J/K.mol H2O= 69.9 J/K.mol THE BALANCE IS: C6H12O6(s) + 6O2(g) —->6CO2(g) + 6H2O(l) = [6 (213.6) + 6 (69.9 )] - [(212.1) + 6(205.0)] = 258.9  =262 J/ K mol.


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