Titration of 25.00 ml of an unknown hcl solution with 0.1550 m naoh starts at a buret reading for naoh of 0.33 ml. the phenolphthalein indicator turns light pink in the acid solution for over 30 seconds at a buret reading of 24.19 ml. 2) what was the volume of naoh dispensed? 3) how many moles of naoh were dispensed? 4) write the balanced molecular equation for the neutralization reaction:

Answers

Q1)  NaOH solution is in the burette and called the titrant  HCl a known volume is in the titration flask and called the titrand. initial burette reading of NaOH - 0.33 mL final buretter reading of NaOH  - 24.19 mL  therefore volume of NaOH added / dispensed - 24.19 - 0.33 = 23.86 mL 23.86 mL of NaOH was dispensed Q2)  phenolphthalein is an acid base reaction indicator that shows a colour change from colourless in neutral and acidic media to pink colour in basic media. phenolphthalein when added to the acid solution is colourless. Once NaOH is added, OH⁻ reacts with H⁺ in acid and is neutralised. After all the H⁺ in medium is used up, the added OH⁻ is no longer neutralised.  in the presence of excess OH⁻, solution becomes basic and phenolphthalein becomes pink. number of moles of NaOH = concentration x volume  number of NaOH moles = 0.1550 mol/L x (23.86 x 10⁻³ L) = 3.698 x 10⁻³ mol NaOH moles added = 3.698 x 10⁻³ mol Q3) Neutralisation reaction is the reaction between an acid and base. H⁺ ions of acid and OH⁻ ions of base react to form water and become neutralised.  when acid and base react they form water and salt. the reaction is as follows; HCl (aq) + NaOH (aq) --> NaCl (aq) + H₂O (l)


0 0
Only authorized users can leave an answer!
Can't find the answer?

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers


More questions