What mass, in grams, of oxygen gas (O2) is contained in a 10.5-liter tank at 27.3 degrees Celsius and 1.83 atmospheres? Show all of the work used to solve this problem.


To find the mass of O₂ in the container we can use the ideal gas law equation  PV = nRT where P - pressure - 1.83 atm V - volume - 10.5 L n - number of moles of O₂ R - universal gas constant - 0.0821 L.atm/mol.K T - temperature in kelvin - 27.3 °C + 273 = 300.3 K substituting the values in the equation  1.83 atm x 10.5 L = n x 0.0821 L.atm/mol.K x 300.3 K n = 0.779 mol  the number of moles of O₂ are 0.779 mol  mass of O₂ = number of moles x molar mass mass of O₂ = 0.779 mol x 32 g/mol = 24.9 g therefore mass of O₂ in the container is 24.9 g

0 0
Only authorized users can leave an answer!
Can't find the answer?

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers

More questions