# Points A(-2,3), B(-5,-4), and C(2,-1) form triangle ABC on a coordinate plane. What is the area of this triangle in square units? 40 29 20

For this case we use the formula of distance between points:  d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)  We have then:  For AB:  AB = root ((- 5 - (- 2)) ^ 2 + (-4-3) ^ 2)  AB = 7.615773106  For AC:  AC = root ((2 - (- 2)) ^ 2 + (-1-3) ^ 2)  AC = 5.656854249  For BC:  BC = root ((2 - (- 5)) ^ 2 + (-1 - (- 4)) ^ 2)  BC = 7.615773106  The area is:  A = root ((s) * (s-a) * (s-b) * (s-c))  Where,  s = (a + b + c) / 2  Substituting values:  s = (7.615773106 + 5.656854249 + 7.615773106) / 2  s = 10.44420023  A = root ((10.44420023) * (10.44420023-7.615773106) * (10.44420023-5.656854249) * (10.44420023-7.615773106))  A = 20 units ^ 2  Answer:  The area of this triangle in square units is:  A = 20 units ^ 2

Only authorized users can leave an answer!

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.