A water balloon is tossed into the air with an upward velocity of 25 ft/s. It’s height h(t) in ft after t seconds is given by the function h(t)=-16^2+25t+3. Show your work. 19. After how many seconds will the balloon hit the ground? (Hint: use the quadratic formula) 20. What will the height be at t=1 second

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For this case we have the following encuacion:  h (t) = - 16t ^ 2 + 25t + 3  We match zero:  -16t ^ 2 + 25t + 3 = 0  Solving the polynomial we have:  t1 = -0.11197537049727824  t2 = 1.6744753704972783  Taking the positive root we have:  t = 1.67 s  The height for t = 1 is:  h (1) = - 16 * (1) ^ 2 + 25 * (1) +3  h (1) = 12 feet  Answer:  The balloon will hit the ground in:   t = 1.67 s  the height will be at t = 1 second:  h (1) = 12 feet


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