Determine b , given that A = 63°, C = 49°, and c = 3.

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A=63° C=49° c=3 b=? Solution: A+B+C=180° 63°+B+49°=180° B+112°=180° Solving for B: B+112°-112°=180°-112° B=68° Using Law of Sines: b/sin B = c/sin C b/sin 68°=3/sin 49° Solving for b: sin 68° (b/sin 68°) = sin 68° (3/sin 49°) b=3 sin 68°/sin 49° sin 68°=0.927183855 sin 49°=0.754709580 b=3(0.927183855)/0.754709580 b=3.685591966 b=3.6856


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