Determine b , given that A = 63°, C = 49°, and c = 3.


A=63° C=49° c=3 b=? Solution: A+B+C=180° 63°+B+49°=180° B+112°=180° Solving for B: B+112°-112°=180°-112° B=68° Using Law of Sines: b/sin B = c/sin C b/sin 68°=3/sin 49° Solving for b: sin 68° (b/sin 68°) = sin 68° (3/sin 49°) b=3 sin 68°/sin 49° sin 68°=0.927183855 sin 49°=0.754709580 b=3(0.927183855)/0.754709580 b=3.685591966 b=3.6856

0 0
Only authorized users can leave an answer!
Can't find the answer?

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers

More questions