# A card is selected at random from a standard 52-card deck. (a) what is the probability that it is an ace? 4/52 (b) what is the probability that it is a heart? .25 (c) what is the probability that it is an ace or a heart

Part (a) is relatively straight forward. There are 4 aces in a standard 52-card deck. So the probability that AN ace is picked is just 4/52. Part (b): Note that there are 4 suits in a standard 52-card deck. So picking hearts will be 13/52 or 1/4. Part (c): The probability condition OR means we need to add the two probabilities because we do not want them simultaneously. So, we end up getting Pr(ace) + Pr(heart). From part (a), we found that picking an ace had a probability of 4/52, which is reduced down to 1/13. From part (b), we found that picking a heart had a probability of 1/4. So, the probability of an ace OR a heart is 1/13 + 1/4 = 4/52 + 13/52 = 17/52.

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