A student did 3/5 of his homework and 8 more problems. then his father came and did one fifth of the homework and the remaining 7 problems. how many problems did they solve?


Suppose the total  number of problems be x this will be given by: (1/5)x+7+(3/5)x+8=x Putting like terms together we get: (1/5x+3/5x)+(7+8)=x 4/5x+15=x 4/5x-x=-15 -1/5x=15 thus x=75 problems

0 0

If x = total number of problems for the homework, Student: Number of problems done = (3/5)x + 8 Father: Number of problems done = (1/5)x + 7 But total number of problems done is x. Then; x = (3/5)x + 8 + (1/5)x + 7 = (4/5)x + 15 (1-4/5)x = 15 (1/5)x = 15 x = 15*5 = 75. ∴ There are 75 problems.

0 0
Only authorized users can leave an answer!
Can't find the answer?

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers

More questions