PLZ HELP ASAP WRITE STANDERED EQAUTION OF A CIRCLE

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R = 5/3 C(9.2, -7.4) r^2 = (x-h)^2 + (y-k)^2 (5/3)^2 = (x - 9.2)^2 + (y + 7.4)^2


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The generic equation of the circle is:  (x-xo) ^ 2 + (y-yo) ^ 2 = r ^ 2  Where,  (xo, yo): coordinate of the center of the circle  r: radius of the circle.  Substituting values we have:  (x-9.2) ^ 2 + (y + 7.4) ^ 2 = (5/3) ^ 2  Rewriting:  (x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9  Answer:  The equation of the circle is:  (x-9.2) ^ 2 + (y + 7.4) ^ 2 = 25/9


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