
The vertices of a right triangle are (–3, 5), (4, –1), and (4, y).
What is the value of y?
A. -3
B. -1
C. 4
D. 5
Answers

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.
Find similar answers
Mathematics, added 2021-03-05 22:16:41

Mathematics, added 2021-03-05 21:10:25
RT has the endpoints (0, 2) and (4, 2). What is its midpoint? (4, 3) (2, 2) (1, 1) (1, 3) ...

Mathematics, added 2021-03-05 20:04:48
RT has the endpoints (0, 2) and (4, 2). What is its midpoint? (4, 3) (2, 2) (1, 1) (1, 3) ...

Mathematics, added 2021-03-05 09:46:48
Find the slope of the line that passes through (4, 1) and (7, –2). 1 1/3 -1/3 -1 ...

Mathematics, added 2021-03-05 08:45:32
Find the slope of the line that passes through (4, 1) and (7, –2). 1 1/3 -1/3 -1 ...

Mathematics, added 2021-03-05 04:20:31

Mathematics, added 2021-03-05 03:15:38

Mathematics, added 2021-03-04 23:42:55

Mathematics, added 2021-03-04 22:08:04



Mathematics, added 2021-03-04 08:20:41
What is the distance between M(2, –7) and N(10, 9)? 68 148 160 320 ...

Mathematics, added 2021-03-04 06:44:05
What is the distance between M(2, –7) and N(10, 9)? 68 148 160 320 ...

Answered by chudung1976
We call A(–3, 5), B(4, –1), and C(4, y), the triangle ABC. We have the coordinates of three vectors: AB(7, -6), BC(0; y+1), and AC(7, y-5) Cause this triangle can be right at A, B or C, we have three cases: + Right at A: AB.AC=0 or 7x7+(-6)x(y-5)=0 and we have 49-6y+30=0 or y=79/6 + Right at B: AB.BC=0 or 7x0+(-6)x(y+1)=0 and we have 0-6y-6=0 or y=-1 Right at C: BC.AC=0 or 0x7+(y+1)x(y-5)=0 and we have (y+1)x(y-5)=0 or y=-1 or y=5 Then, we have 3 values of y.