Which of the following is the solution to 4 | x + 3 | ≥ 8?
A. x ≤ -5 and x ≥ -1
B. x ≥ -1
C. x ≤ -5 or x ≥ -1
D. x ≥ -5 or x ≥ -1
Answers
Only authorized users can leave an answer!
Can't find the answer?
If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.
Find similar answersMore questions
Mathematics, added 2021-04-18 05:43:12
Mathematics, added 2021-04-18 03:52:35
Mathematics, added 2021-04-16 04:45:24
Mathematics, added 2021-04-16 03:14:30
Answered by jimmyrepin
Either 4(x + 3) >= 8 or 4(x + 3) <= -8 4x + 12 >=8 4x >= =4 x >= -1 or 4x + 12 <= -8 4x <= -20 x <= -5 Answer is C
Answered by tonb
First we get rid of the 4 by dividing by it: 4 | x + 3 | ≥ 8 => | x + 3 | ≥ 2 Then eliminate the absolute operator like this: | x + 3 | ≥ 2 => -x-3 ≥ 2 or x+3 ≥ 2 Simplify: -x ≥ 5 or x ≥ -1=> x ≤ -5 or x ≥ -1 That's answer C