# Please help me with the first question

## Answers

Only authorized users can leave an answer!

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answersOnly authorized users can leave an answer!

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers
Answered by

mathstudent55I assume the carpet has the shape of a rectangle. Let L = length Let W = width The area is 192 ft^2. LW = 192 The perimeter is 56 ft. 2L + 2W = 56 We have a system of 2 equation in 2 unknowns. LW = 1922L + 2W = 56 Divide the second equation by 2: L + W = 28 Subtract W from both sides. L = 28 - W Substitute 28 - W for L in the first equation. LW = 192 (28 - W)W = 192 28W - W^2 = 192 W^2 - 28W + 192 = 0 (W - 12)(W - 16) = 0 W - 12 = 0 or W - 16 = 0 W = 12 or W = 16 L = 28 - W For W = 12: L = 28 - 12 = 16 For W = 16" L = 28 - 16 = 12 We get: length = 16 and width = 12 or: length = 12 and width = 16 Either answer is correct, but since people think the length is longer than the width, answer with a longer length than the width. Answer: Length = 16 ft Width = 12 ft