## Answers

Only authorized users can leave an answer!

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answersOnly authorized users can leave an answer!

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers
Answered by

calculistaThe correct question is The area of a rectangle is 432 square centimeters. What would the new area be if the length of the rectangle was decreased by 10% and the width of the rectangle was increased by 10%? Express your answer to the nearest whole number. let x------> the length of the rectangle y-------> the width of the rectangle we know that area of rectangle=x*y area of rectangle=432 cm² so 432=x*y----> equation 1 if the length of the rectangle was decreased by 10% and the width of the rectangle was increased by 10% 10% of x is 0.10x 10% of y is 0.10y x1=x-0.10x---> 0.90x y1=y+0.10x---> 1.10y new area=(0.90x)*(1.10y)----> 0.99*[x*y] new area= 0.99*[x*y]-----> new area=0.99*[original area] new area=0.99*432----> 427.68 cm² new area=428 cm² the answer is the new area is 428 cm²