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calculistaThe correct question is The area of a rectangle is 432 square centimeters. What would the new area be if the length of the rectangle was decreased by 10% and the width of the rectangle was increased by 10%? Express your answer to the nearest whole number. let x------> the length of the rectangle y-------> the width of the rectangle we know that area of rectangle=x*y area of rectangle=432 cm² so 432=x*y----> equation 1 if the length of the rectangle was decreased by 10% and the width of the rectangle was increased by 10% 10% of x is 0.10x 10% of y is 0.10y x1=x-0.10x---> 0.90x y1=y+0.10x---> 1.10y new area=(0.90x)*(1.10y)----> 0.99*[x*y] new area= 0.99*[x*y]-----> new area=0.99*[original area] new area=0.99*432----> 427.68 cm² new area=428 cm² the answer is the new area is 428 cm²