Through [0, -7/5] and perpendicular to 3x-2y=6
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Answered by mathdad1965
Find a line going through the point (0, -7/5) and perpendicular to the equation 3x - 2y = 6. 3x - 2y = 6 -2y = -3x + 6 y = (3/2)x - 3 The slope of the equation we seek must be the negative reciprocal of (3/2), which is -2/3. So, m = -2/3 Use the point-slope formula. See the picture.