# Mr. Dawson was given three loan options by his bank in order to purchase a plot of land. The functions below model the cost of the plot of land after x years.

Mr. Dawson plans to finance the loan of his choice for 30 years. The least affordable loan option for Mr. Dawson is option

.

## Answers

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answersMathematics, added 2021-08-02 23:09:28

Mathematics, added 2021-08-01 07:20:06

Mathematics, added 2021-08-01 05:20:36

Mathematics, added 2021-07-30 22:37:55

Mathematics, added 2021-07-30 21:32:09

Mathematics, added 2021-07-28 22:50:00

What is the point slope form of a line with a slope 4/5 that contains the point (-2,1) ...

Mathematics, added 2021-07-28 21:32:15

What is the point slope form of a line with a slope 4/5 that contains the point (-2,1) ...

Mathematics, added 2021-07-27 09:21:10

Mathematics, added 2021-07-27 08:09:30

Mathematics, added 2021-07-25 18:58:34

In what quadrant does the angle 12pi/5 terminate? I II III IV ...

Mathematics, added 2021-07-25 17:52:36

In what quadrant does the angle 12pi/5 terminate? I II III IV ...

Answered by

saadhussain514Mr. Dawson plans to finance the loan of his choice for 30 years. In order to find the least affordable loan option for Mr. Dawson, we will have to substitute x = 30 in each of the given equations and the best option would have the lowest answer. Option A: f(x) = 8000 (1 + 0.15/12) ¹²ˣ Susbstituting x = 30. f(30) = 8000 (1 + 0.15/12)³⁶⁰ f(30) = 8000 (1 + 0.15/12)³⁶⁰ f(30) = 8000 × 87.54 f(30) = 700,327.96 Option B: g(x) = 700 x + 8000 Susbstituting x = 30. g(x) = 700 (30) + 8000 g(x) = 21000 + 8000 g(x) = 29,000 Option C: h(x) = x² + 400x + 8000 Susbstituting x = 30. h(x) = 30² + 400(30) + 8000 h(x) = 900 + 12000 + 8000 h(x) = 20,900 The least affordable loan option for Mr. Dawson is option C.