Find two numbers whose difference is 150 and whose product is a minimum. step 1 if two numbers have a difference of 150, and one of them is x + 150, then the other i

Answers

The lowest possible product would be -5625 given the numbers 75 and -75.  We can find this by setting the first number as x + 150, which we see in the equation given above. The other number would have to be simply x since it has to have a 150 difference.  Next we'll multiply the numbers together.  x(x+150) x^2 + 150x Now we want to minimize this as much as possible, so we'll find the vertex of this quadratic graph. You can do this by finding the x value as -b/2a, where b is the number attached to x and a is the number attached to x^2 -b/2a = -150/2(1) = -150/2 = -75 So we know one of the values is -75. We can plug that into the equation to find the second.  x + 150  -75 + 150  75


0 0
Only authorized users can leave an answer!
Can't find the answer?

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers


More questions