# When volleyballs are purchased, they are not fully inflated. a partially inflated volleyball can be modeled by a sphere whose volume is approximately 180?

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LouliI added a screenshot with the complete question. Answer: The radius increased by 0.6 in Explanation: 1- getting the radius before the ball is fully inflated: volume of sphere = We are given that the volume before the ball is fully inflated is 180 in³. Therefore, we can solve for the radius as follows: 180 = 135 = π * r³ 42.9718 = r³ radius = 3.5026 in 2- getting the radius after the ball is fully inflated: volume of sphere = We are given that the volume after the ball is fully inflated is 294 in³. Therefore, we can solve for the radius as follows: 294 = 220.5 = π * r³ 70.187 = r³ radius = 4.124958 in 3- getting the increase in the radius: increase in radius = radius after inflation - radius before inflation increase in radius = 4.124958 - 3.5026 increase in radius = 0.622 which is approximately 0.6 in Hope this helps :)