The midpoint of segment AB is (6, 5). The coordinates of point A are (7, 10). Find the coordinates of point
b.
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A circle has the equation x2 + y2 – x + 10y + 13 = 0. What is the radius of this circle? ...
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A circle has the equation x2 + y2 – x + 10y + 13 = 0. What is the radius of this circle? ...
Answered by tramserran
Mx = (Ax + Bx)/2 My = (Ay + By) 6 = (7 + Bx)/2 5 = (10 + By)/2 12 = 7 + Bx 10 = 10 + By 5 = Bx 0 = By (5,0)