# How many 5-digit numbers can be formed from the integers 1, 2, ... , 9 if no digit can appear more than twice?

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Answered by

npiazza90p8qc3q5 digit number with no repeats 1st digit has 9 possibilities 2nd digit has 8 possibilities 3rd digit has 7 possibilities 4th digit has 6 possibilities 5th fight has 5 possibilities Therefore the answer is: 9 x 8 x 7 x 6 x 5 = 72 x 210 = 15,120