How many 5-digit numbers can be formed from the integers 1, 2, ... , 9 if no digit can appear more than twice?


5 digit number with no repeats 1st digit has 9 possibilities 2nd digit has 8 possibilities 3rd digit has 7 possibilities 4th digit has 6 possibilities 5th fight has 5 possibilities Therefore the answer is: 9 x 8 x 7 x 6 x 5 = 72 x 210 = 15,120

0 0
Only authorized users can leave an answer!
Can't find the answer?

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answers

More questions