A car moves along a curved road of diameter 2 km. If the maximum velocity for safe driving on this path is 30 m/s, at what angle has the road been banked? (Ignore friction.)

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The maximum velocity in a banked road, ignoring friction, is given by; v = Sqrt (Rg tan ∅), where R = Radius of the curved road = 2*1000/2 = 1000 m, g = gravitational acceleration = 9.81 m/s^2, ∅ = Angle of bank. Substituting; 30 m/s = Sqrt (1000*9.81*tan∅) 30^2 = 1000*9.81*tan∅ tan ∅ = (30^2)/(1000*9.81) = 0.0917 ∅ = tan^-1(0.0917) = 5.24° Therefore, the road has been banked at 5.24°.


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