# A spring-loaded gun can fire a projectile to a height h if it is fired straight up. if the same gun is pointed at an angle of 45◦ from the vertical, what maximum height h45◦ can now be reached by the projectile

## Answers

If you are not satisfied with the answer or you can’t find one, then try to use the search above or find similar answers below.

Find similar answersPhysics, added 2020-09-10 09:35:22

Physics, added 2020-09-10 08:02:56

Physics, added 2020-09-07 00:05:06

Explain why cooler stars are red and hotter stars are blue ...

Physics, added 2020-09-06 23:02:22

Explain why cooler stars are red and hotter stars are blue ...

Physics, added 2020-09-06 21:25:53

How many calories is required to raise the temp from 11to 23? ...

Physics, added 2020-09-06 19:27:30

How many calories is required to raise the temp from 11to 23? ...

Physics, added 2020-08-27 15:39:46

The first artificial satellite to be launched into space was called _____________. ...

Physics, added 2020-08-27 13:51:28

The first artificial satellite to be launched into space was called _____________. ...

Answered by

jushmkWhen firing straight up: v^2 = u^2 - 2gh, where v = final velocity = 0, u = initial velocity, g = gravitational acceleration, h = maximum height attained. Then, 0 = u^2 - 2gh u = Sqrt (2gh) ---- (1) When firing at 45°, Initial velocity, U = u Sin 45 = Sqrt (2gh)·Sin 45 Maximum height, H = U^2*(Sin Ф)^2/2g substituting; H = [Sqrt (2gh)·Sin 45]^2*(Sin 45)^2]/2g H = [2gh*(Sin 45)^2*(Sin 45)^2]/2g H = [h*(Sin 45)^4] = h/4 Therefore, maximum height when the gun fires at 45° is a quarter of maximum height when the gun fires vertically up.