If an object is projected upward with an initial velocity of 127 ft per​ sec, its height h after t seconds is h equals negative 16 t squared plus 127 t. find the height of the object after 2 seconds. the height of the object after 2 seconds is nothing ft.


Answer: 190 ft Explanation: 1) In this problem you are given with the equation for the height, h(t) = - 16t² - 127 t and are asked for the height after t = 2 seconds. 2) The work consists is finding h(2), i.e. substitue t for 2 in the equation: h(2) = -16(2)² + 127(2) = -16(4) + 254 = - 64 + 254 = 190 ft

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